89 lines
3.1 KiB
C#
89 lines
3.1 KiB
C#
using System;
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using System.Collections.Generic;
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using System.Drawing.Drawing2D;
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using System.Linq;
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using System.Text;
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using System.Threading.Tasks;
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namespace CanFly.Canvas.Helper
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{
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public static class PointHelper
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{
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public static Point ToPoint(this PointF pf)
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{
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return new Point((int)pf.X, (int)pf.Y);
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}
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/// <summary>
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/// 将相对于控件的坐标转换为相对于图像的坐标
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/// </summary>
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/// <param name="p">控件中指定点的点位坐标，坐标原点为控件左上角</param>
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/// <returns>该点以图像坐标系为基准的坐标值，坐标原点为图像左上角</returns>
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public static PointF ToImageCoordinate(this Point p, Matrix m)
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{
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PointF pf = new PointF(p.X, p.Y);
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return ToImageCoordinate(pf, m);
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}
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/// <summary>
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/// 将相对于控件的坐标转换为相对于图像的坐标
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/// </summary>
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/// <param name="p">控件中指定点的点位坐标，坐标原点为控件左上角</param>
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/// <returns>该点以图像坐标系为基准的坐标值，坐标原点为图像左上角</returns>
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public static PointF ToImageCoordinate(this PointF p, Matrix m)
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{
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PointF[] ps = new PointF[] { p };
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Matrix invertMatrix = m.Clone();
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//想要从旧空间到新空间的逆变换，所以我们需要对这个矩阵求逆
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invertMatrix.Invert();
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invertMatrix.TransformPoints(ps);
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return ps[0];
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}
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/// <summary>
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/// 将相对于图像的坐标转换为相对于控件坐标系
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/// </summary>
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/// <param name="p">图像中指定点的点位坐标，坐标原点为图像左上角</param>
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/// <returns>该点以空间坐标系为基准的坐标值，坐标原点为空间坐左上角</returns>
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public static PointF ToControlCoordinate(this PointF p, Matrix m)
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{
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PointF[] ps = new PointF[] { p };
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m.TransformPoints(ps);
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return ps[0];
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}
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public static float Distance(PointF p1, PointF p2)
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{
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return (float)Math.Sqrt(Math.Pow(p2.X - p1.X, 2) + Math.Pow(p2.Y - p1.Y, 2));
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}
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public static float DistanceToLine(PointF point, PointF start, PointF end)
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{
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float lineLengthSquared = DistanceSquared(start, end);
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if (lineLengthSquared == 0)
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{
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return Distance(point, start); // 线段的两个端点重合
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}
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float t = ((point.X - start.X) * (end.X - start.X) + (point.Y - start.Y) * (end.Y - start.Y)) / lineLengthSquared;
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t = Math.Clamp(t, 0, 1); // 限制 t 在 [0, 1] 范围内
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PointF projection = new PointF(
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start.X + t * (end.X - start.X),
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start.Y + t * (end.Y - start.Y));
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return Distance(point, projection);
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}
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public static float DistanceSquared(PointF p1, PointF p2)
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{
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return (float)(Math.Pow(p2.X - p1.X, 2) + Math.Pow(p2.Y - p1.Y, 2));
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}
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}
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}
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