update sql/quartz.sql.
解决 Can’t write; duplicate key in table ‘qrtz_triggers’
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@ -48,7 +48,7 @@ create table QRTZ_TRIGGERS (
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misfire_instr smallint(2) null comment '补偿执行的策略',
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job_data blob null comment '存放持久化job对象',
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primary key (sched_name, trigger_name, trigger_group),
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foreign key (sched_name, job_name, job_group) references QRTZ_JOB_DETAILS(sched_name, job_name, job_group)
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constraint FK_QRTZ_TRIGGERS foreign key (sched_name, job_name, job_group) references QRTZ_JOB_DETAILS(sched_name, job_name, job_group)
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) engine=innodb comment = '触发器详细信息表';
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-- ----------------------------
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