if("" != dictType)和if(dictType)的意义是一样的,判断不等于空字符串,和判断存在的结果是一样的。

This commit is contained in:
xialuotang 2021-12-31 11:08:12 +08:00
parent 6ef899d000
commit ab2b27381a

View File

@ -217,7 +217,7 @@
></el-option>
</el-select>
</el-form-item>
#elseif($column.htmlType == "select" && $dictType)
#elseif($column.htmlType == "select" && "" == $dictType)
<el-form-item label="${comment}" prop="${field}">
<el-select v-model="form.${field}" placeholder="请选择${comment}">
<el-option label="请选择字典生成" value="" />
@ -234,7 +234,7 @@
</el-checkbox>
</el-checkbox-group>
</el-form-item>
#elseif($column.htmlType == "checkbox" && $dictType)
#elseif($column.htmlType == "checkbox" && "" == $dictType)
<el-form-item label="${comment}">
<el-checkbox-group v-model="form.${field}">
<el-checkbox>请选择字典生成</el-checkbox>
@ -251,7 +251,7 @@
>{{dict.label}}</el-radio>
</el-radio-group>
</el-form-item>
#elseif($column.htmlType == "radio" && $dictType)
#elseif($column.htmlType == "radio" && "" == $dictType)
<el-form-item label="${comment}">
<el-radio-group v-model="form.${field}">
<el-radio label="1">请选择字典生成</el-radio>